If the area bounded by the x-axis, the curve `y=f(x), (f(x)gt0)" and the lines "x=1, x=b " is equal to "sqrt(b^(2)+1)-sqrt(2)" for all "bgt1,` then find f(x).

The area bounded by the x-axis, the curve y=f(x), and the lines x=1,x=b is equal to sqrt(b^2+1)-sqrt(2) for all b >1, then f(x) is

The area bounded by the x-axis, the curve y=f(x), and the lines x=1,x=b is equal to sqrt(b^2+1)-sqrt(2) for all b >1, then f(x) is

The area bounded by the x-axis, the curve y=f(x), and the lines x=1,x=b is equal to sqrt(b^2+1)-sqrt(2) for all b >1, then f(x) is

The area bounded by the X-axis, the cure y = f(x) and the lines x = 1 and x = b is equal to sqrt(b^(2)+1)-sqrt(2) for all b gt 1 then f(x) is

The area bounded by the X-axis, the cure y = f(x) and the lines x = 1 and x = b is equal to sqrt(b^(2)+1)-sqrt(2) for all b gt 1 then f(x) is

The area bounded by the x-axis,the curve y=f(x), and the lines x=1,x=b is equal to sqrt(b^(2)+1)-sqrt(2) for all b>1, then f(x) is sqrt(x-1)(b)sqrt(x+1)sqrt(x^(2)+1)(d)(x)/(sqrt(1+x^(2)))

The area bounded by the x-axis the curve y = f(x) and the lines x = a and x = b is equal to sqrt(b^(2) - a^(2)) AA b > a (a is constant). Find one such f(x).

The area bounded by the x-axis the curve y = f(x) and the lines x = a and x = b is equal to sqrt(b^(2) - a^(2)) AA b > a (a is constant). Find one such f(x).