The line of intersection of the planes `vecr . (3 hati - hatj + hatk) =1 and vecr. (hati+ 4 hatj -2 hatk)=2` is:

The vector parallel to the line of intersection of the planes vecr.(3hati-hatj+hatk) = 1 and vecr.(hati+4hatj-2hatk)=2 is :

The vector parallel to the line of intersection of the planes vecr.(3hati-hatj+hatk) = 1 and vecr.(hati+4hatj-2hatk)=2 is :

Find the line of intersection of the planes vecr.(3hati-hatj+hatk)=1 and vecr.(hati+4hatj-2hatk)=2

The vector parallel to the line of intersection of the planes vecr.(3hati-hatj+hatk) = 1 and vecr.(hati+4hatj-2hatk)=2 is : a) -2hati-7hatj+13hatk b) 2hati+7hatj-13hatk c) 2hati+7hatj+13hatk d) -2hati+7hatj+13hatk

The line of intersection of the planes vecr.(3hati-hatj+hatk)=1 and vecr.(hati+4hatj-2hatk)=2 is parallel to the vector (A) 2hati+7hatj+13hatk (B) -2hati+7hatj+13hatk (C) -2hati-7hatj+13hatk (D) 2hati-7hatj-13hatk

The line of intersection of the planes vecr.(3hati-hatj+hatk)=1 and vecr.(hati+4hatj-2hatk)=2, is (A) (x-6/13)/2=(y-5/13)/-7=z/-13 (B) (x-6/13)/2=(y-5/13)/7=z/-13 (C) (x-4/7)/-2=y/7=(z-5/7)/13 (D) (x-4/7)/-2=y/-7=(z+5/7)/13

The angle between hati and line of the intersection of the planes vecr.( hati+2 hatj+ 3 hatk)=0 and vecr.(3 hati+3 hatj+ hatk)=0 is __

A unit vector parallel to the intersection of the planes vecr.(hati - hatj + hatk) =5 and vecr.( 2 hati + hatj - 3 hatk) =4 is

Find the equation of the plane through the point hati+4hatj-2hatk and perpendicular to the line of intersection of the planes vecr.(hati+hatj+hatk)=10 and vecr.(2hati-hatj+3hatk)=18.