A body of mass `2 kg` has an initial velocity of `3 m s^-1` along `OE` and it is subjected to a force of `4 N` in `O F` direction perpendicular to `O E`. Find the distance of the body from `O` after `4 s`.
.

A body mass 2kg has an initial velocity of 3 metre//sec along OE and it is subject to a force of 4N in a direction perpendicular to OE. The distance of body from O after 4 sec will be:

A body mass 2kg has an initial velocity of 3 metre//sec along OE and it is subject to a force of 4N in a direction perpendicular to OE. The distance of body from O after 4 sec will be:

A body mass 2kg has an initial velocity of 3 metre//sec along OE and it is subject to a force of 4N in a direction perpendicular to OE. The distance of body from O after 4 sec will be:

Assertion : A body of mass 4 kg has an initial velocity 5hat(i)ms^(-1) . It is subjected to a force of 4hat(j)N . The displacement of body from origin after 4 s will be 21.5 m . Reason : The equation v=u+a t can be applied to obtain v if a is constant.

Assertion : A body of mass 4 kg has an initial velocity 5hat(i)ms^(-1) . It is subjected to a force of 4hat(j)N . The displacement of body from origin after 4 s will be 21.5 m . Reason : The equation v=u+a t can be applied to obtain v if a is constant.

A body of mass 2kg has an initial speed 5 m/s. A force acts as it for some time in the direction of motion. The force-time graph is shown in figure. Find the final speed of the body.