A gas is expanded from volume `V_(1)` to `V_(2` through three different process:
a. Reversible adiabatic
b. Reversible isothermal
c. Irreversible adiabatic (against a constant external pressure `P_(ex))`
The correct option is

A sample of gas is compressed from an initial volume of 2v_(0) " to " v_(0) using three different processes. First: Using reversible isothermal Second: Using reversible adiabatic Third: Using irreversible adiabatic under a constant external pressure then

A sample of gas is compressed from an initial volume of 2v_(0) " to " v_(0) using three different processes. First: Using reversible isothermal Second: Using reversible adiabatic Third: Using irreversible adiabatic under a constant external pressure then

A gas is expanded from volume V_(0) = 2V_(0) under three different processes. Process 1 is isobaric process, process 2 is isothermal and process 3 is adiabatic. Let DeltaU_(1), DeltaU_(2) and DeltaU_(3) be the change in internal energy of the gas in these three processes. then

A gas is expanded from volume V_(0) = 2V_(0) under three different processes. Process 1 is isobaric process, process 2 is isothermal and process 3 is adiabatic. Let DeltaU_(1), DeltaU_(2) and DeltaU_(3) be the change in internal energy of the gas in these three processes. then

The ratio of slopes of P-V plots for reversible adiabatic process and reversible isothermal process of an ideal gas is equal to :

A gaseous sample is generally allowed to do only expansion // compression type work against its surroundings The work done in case of an irreversible expansion ( in the intermediate stages of expansion // compression the states of gases are not defined). The work done can be calculated using dw= -P_(ext)dV while in case of reversible process the work done can be calculated using dw= -PdV where P is pressure of gas at some intermediate stages. Like for an isothermal reversible process. Since P=(nRT)/(V) , so w=intdW= - underset(v_(i))overset(v_(f))int(nRT)/(V).dV= -nRT ln(V_(f)/(V_(i))) Since dw= PdV so magnitude of work done can also be calculated by calculating the area under the PV curve of the reversible process in PV diagram. If four identical samples of an ideal gas initially at similar state (P_(0),V_(0),T_(0)) are allowed to expand to double their volumes by four different process. I: by isothermal irreversible process II: by reversible process having equation P^(2)V= constant III. by reversible adiabatic process IV. by irreversible adiabatic expansion against constant external pressure. Then, in the graph shown in the final state is represented by four different points then, the correct match can be