A man is standing on a weighing machine placed in a lift. When stationary his weight is recorded as 40 kg . If the lift is accelerated upwards with an acceleration of `2m//s^(2)` , then the weight recorded in the machine will be `(g=10m//s^(2))`

The mass of lift is 500 kg. When it ascends with an acceleration of 2m//s^(2) ,the tension in the cable will be [g=10m//s^(2)]

A man of mass 60 kg is in a lift and lift is accelerating upwards with acceleration 4 m//s^(2) . Calculate effective weight of man in lift.

A man of mass 60 kg is in a lift and lift is accelerating upwards with acceleration 4 m//s^(2) . Calculate effective weight of man in lift.

A man of mass 60 kg is in a lift and lift is accelerating upwards with acceleration 4 m//s^(2) . Calculate effective weight of man in lift.

A man of weight 80 kg is standing in an elevator which is moving with an acceleration of 6m//s^(2) in upward direction. The apparent weight of the man will be (g=10m//s^(2))

A man of weight 80 kg is standing in an elevator which is moving with an acceleration of 6m//s^(2) in upward direction. The apparent weight of the man will be (g=10m//s^(2))

The mass of a lift is 600 kg and it is moving upwards with a uniform acceleration of 2m//s^(2) . Then the tension in the cable of the lift is-

A man of mass 60 kg records his weight on a weighing machine placed inside a lift . The ratio of the weights of the man recorded when the lift is ascending up with a uniform speed of 2 m/s to when it is descending down with a uniform speed of 4 m/s will be

A lift of mass 200 kg is moving upward with an acceleration of 3m//s^(2) . If g=10 m//s^(2) then the tension of string of the lift will be :