Home
Class 12
CHEMISTRY
Transitional kinetic energy of a gas mol...

Transitional kinetic energy of a gas molecule________

A

is constant at constant temperature

B

depends on quantity of gas

C

does not change with volume at a given temperature

D

is same for all gases at a given temperature

Text Solution

Verified by Experts

The correct Answer is:
A, C, D
Promotional Banner

Topper's Solved these Questions

  • STATES OF MATTER

    AAKASH SERIES|Exercise LECTURE SHEET -EXERCISE-III (KINETIC MOLECULAR THEORY, MOLECULAR VELOCITY, MEAN FREE PATH, COLLISION FREQUENCY) (LINKED COMPREHENSION TYPE QUESTIONS) (PASSAGE-I)|3 Videos

  • STATES OF MATTER

    AAKASH SERIES|Exercise LECTURE SHEET -EXERCISE-III (KINETIC MOLECULAR THEORY, MOLECULAR VELOCITY, MEAN FREE PATH, COLLISION FREQUENCY) (MATRIX MATCHING TYPE QUESTIONS)|2 Videos

  • STATES OF MATTER

    AAKASH SERIES|Exercise LECTURE SHEET -EXERCISE-III (KINETIC MOLECULAR THEORY, MOLECULAR VELOCITY, MEAN FREE PATH, COLLISION FREQUENCY) (STRAIGHT OBJECTIVE TYPE QUESTIONS)|15 Videos

  • SOLUTIONS

    AAKASH SERIES|Exercise Objective Exercise -4|50 Videos

  • STOICHIOMETRY

    AAKASH SERIES|Exercise PRACTICE SHEET (ADVANCED) (INTEGER TYPE QUESTION)|2 Videos

Similar Questions

Explore conceptually related problems

The temperature at which the average translational kinetic energy of gas molecules, will be equal to that of an alpha- particle, accelerated through a potential difference of 1 volt, from rest is:

The mean translational kinetic energy of a molecule of an ideal gas at temperature T K is

(A): The total translational kinetic energy of all the molecules of a given mass of an ideal gas is 1.5 times the product of its pressure and its volume. (R): The molecules of a gas collide with each other and the velocities of the molecules change due to the collision.

Derive an expression for kinetic energy of gas molecules.

Give an equation to calculate the kinetic energy of gas molecules.