Home
Class 12
CHEMISTRY
Plots of log K Vs (1)/(T) plots shows an...

Plots of log K Vs `(1)/(T)` plots shows an intercept of 2 on y-axis with a slope of `45^(@)` for the studied reactions. Assuming that `Delta H^(@) and Delta S^(@)` as temperature independent, select the correct statement

A

`Delta G^(@) = - 2.75` K. cal

B

`Delta S^(@)` = 4.606 cal

C

`Delta H^(@)` = - 4.606 cal

D

k = 100.8

Text Solution

Verified by Experts

The correct Answer is:
A, C, D
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LEVEL -II) (LECTURE SHEET (ADVANCED))INTEGER TYPE QUESTIONS|5 Videos
  • CHEMICAL EQUILIBRIUM

    AAKASH SERIES|Exercise PRACTICE SHEET (ADVANCED)(STRAIGHT OBJECTIVE TYPE QUESTIONS )|20 Videos
  • CHEMICAL EQUILIBRIUM

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LEVEL -II) (LECTURE SHEET (ADVANCED))STRAIGHT OBJECTIVE TYPE QUESTIONS|20 Videos
  • CARBOXYLIC ACIDS AND DERIVATIVES

    AAKASH SERIES|Exercise CONVERSIONS|19 Videos
  • CHEMICAL KINETCS

    AAKASH SERIES|Exercise EXERCISE - 3.2|45 Videos

Similar Questions

Explore conceptually related problems

The temperature of K at which Delta G =0 for a given reaction with Delta H= -20.5 kJ mol^(-1) and Delta S =- 50.0 JK^(-1)mol^(-1)

In the conversion of lime stone to lime, CaCO_(3(s)) rarr CaO_((s)) + CO_(2(g)) , the values of Delta H^(@) and Delta S^(@) are + 179.1 kJ mol^(-1) and 160.2 JK^(-1) mol^(-1) respectively at 298K and 1 bar. Assuming, Delta H^(@) and Delta S^(@) do not change with temperature, temperature above which conversion of lime stone to lime will be spontaneous is

Suppose that a reaction has Delta H= -400kJ and Delta S = - 50J//K . A t what temperature range will it change from spontaneous to non-spontaneous?

What is the DeltaS^(@) for the reaction in cal if the graph of ln K vs 1//T is as follows.

Which of the following statement(s) are true regarding the log K vs 1/T plots shown in the given diagram. Plot P shows that the energy of activation is independent of temperature