Find the kinetic energy of the `alpha` - particle emitted in the decay `^238 Pu rarr ^234 U + alpha`. The atomic masses needed are as following:
`^238 Pu 238.04955 u`
`^234 U 234.04095 u`
`^4 He 4.002603 u`.
Neglect any recoil of the residual nucleus.

Calculate the energy released in the alpha decay of ^238 Pu to ^234 U , the masses involved being m_Pu=238.04955u , m_U= 234.04095u and m_He =4.002603u

The partlcles emitted 1n the decay of ""_(92)^(238)U to ""_(92)^(234)U

Find the kinetic energy of emitted a-particles in the following nuclear reaction: ""_(94)Pu^(238) to ""_(92)U^(234) + ""_(2)He^(4) m(Pu^(238)) = 238.04954 amu m(U^(234)) = 234.04096 amu m(""_(2)He^(4)) = 4.002603 amu

The radionuclide .^(238)U decays by emitting an alpha particle. .^(238)Uto.^(234)Th+.^(4)He The atomic masses of the three isotopes are .^(238)" "U 238.05079 am u .^(234) U" "234.040363 am u .^(4) He " " 4.00260 am u What is the maximum kinetic energy of the emitted alpha particle. Express your answer in Joule. ( 1am u = 1.67 xx 10^(-27)kg )

The number of alpha and beta -particle emitted in the transformation ""_(92)^(238)U to ""_(92)^(234)U

How many alpha and beta -particles are emitted in the transformation ""_(92)^(238)U rarr ""_(92)^(234)U

How many alpha and beta -particles are emitted in the transformation ""_(92)^(238)U rarr ""_(92)^(234)U