An artificial satellite is describing an equatorial orbit at `3600 km` above the earth's surface. Calculate its period of revolution? Take earth radius `6400km`.

An artificial satellite is describing an eqatorial orbit at 1600 km above the surface of the earth. Calculate its orbital speed and the period of revolution. If the satellite is travelling in the same direction as the rotateion of the earth (i.e., from west to east), calculate the interval between two successive times at which it will appear vertically overhead to an observer at a fixed point on the equator. Radius of earth = 6400km.

An artificial satellite is at a height of 35780 km .from the earth's surface. What is the period of revolution of this satellite?

An artificial satellite is at a height of 35780 km from the Earth's surface .What is the period of revolution of this satellite ?

An artificial satellite is revolving in a circular orbit at height of 1200 km above the surface of the earth. If the radius of the earth is 6400 km and mass is 6xx10^(24) kg , the orbital velocity is

A satellite ils launched into a circular orbit 1600km above the surface of the earth. Find the period of revolution if the radius of the earth is R=6400km and the acceleration due to gravity is 9.8ms^(-2) . At what height from the ground should it be launched so that it may appear stationary over a point on the earth's equator?

A satellite ils launched into a circular orbit 1600km above the surface of the earth. Find the period of revolution if the radius of the earth is R=6400km and the acceleration due to gravity is 9.8ms^(-2) . At what height from the ground should it be launched so that it may appear stationary over a point on the earth's equator?

An artificial satellite is revolving in a circular orbit at a height of 1200km above the surface of the earth. If the radius of the earth is 6400km, mass is 6xx10^24 kg find the orbital velocity (G=6.67xx10^(-11) Nm^2//kg^2)

Calculate the speed and period of revolution of a satellite orbiting at a height of 700 km above the earth's surface. Assume the orbit to be circular. Take radius of earth as 6400 km and g at the centre of earth to be 9.8 m//s^2