A particle of `m` is executing `SHM`about the origin on x- axis frequencxy `sqrt((ka)/(pi m))`, where `k` is a constant and a is the amplitude Find its potential energy if `x` is the displecement at time t:

A particle of mass (m) is executing oscillations about the origin on the (x) axis. Its potential energy is V(x) = k|x|^3 where (k) is a positive constant. If the amplitude of oscillation is a, then its time period (T) is.

A particle of mass (m) is executing oscillations about the origin on the (x) axis. Its potential energy is V(x) = k|x|^3 where (k) is a positive constant. If the amplitude of oscillation is a, then its time period (T) is.

A particle of mass (m) is executing oscillations about the origin on the (x) axis. Its potential energy is V(x) = k|x|^3 where (k) is a positive constant. If the amplitude of oscillation is a, then its time period (T) is.

A particle of mass (m) is executing oscillations about the origin on the x axis. Its potential energy is V(x) = k|x|^3 where k is a positive constant. If the amplitude of oscillation is a, then its time period (T) is.

A particle of mass (m) is executing oscillations about the origin on the (x) axis. Its potential energy is V(x) = k|x|^3 where (k) is a positive constant. If the amplitude of oscillation is a, then its time period (T) is.

A particle of mass m is executing oscillation about the origin on X- axis Its potential energy is V(x)=kIxI Where K is a positive constant If the amplitude oscillation is a, then its time period T is proportional