Prove that `tan(pi/4+1/2cos^(-1)(a/b))+tan(pi/4-1/2cos^(-1)(a/b))=(2b)/a`.

Prove that tan(pi/4+1/2 cos^-1(a/b))+tan(pi/4-1/2 cos^-1(a/b))=(2b)/a

Prove that tan(pi/4+1/2 cos^-1(a/b))+tan(pi/4-1/2 cos^-1(a/b))=(2b)/a

answer any one question : (ii) prove that , tan(pi/4 +1/2 (cos ^(-1) (a/b))+ tan(pi/4-1/2 (cos ^(-1) (a/b))=(2b)/a.

tan((pi)/4+1/2"cos"^(-1)a/b)+tan((pi)/4-1/2"cos"^(-1)a/b)=

Prove that tan(pi/4 +1/2 cos^(-1) (a/b)) + tan^(-1) (pi/4 -1/2 cos^(-1) (a/b)) =2b/a

Prove the followings : tan(pi/4+1/2"cos"^(-1)a/b)+tan(pi/4-1/2"cos"^(-1)a/b)=(2b)/a

Prove that tan{(pi)/4 + 1/2 Cos^(-1)((a)/(b))}+tan{((pi)/4-1/2 Cos^(-1)a/b)} = (2b)/a .

Prove that : "tan"(pi/4 +1/2 "cos"^(-1) a/b) +"tan"(pi/4 -1/2 "cos"^(-1) a/b) =(2b)/a

Prove the following: tan[pi/4+1/2cos^(-1)(a/b)]+tan[pi/4-1/2cos^(-1)(a/b)]=(2b)/a