If the curves `y^2=6x,9x^2+by^2=16`, cut each other at right angles then the value of `b` is

If the curves y^2=6x , 9x^2+by^2=16 intersect each other at right angles then the value of b is: (1) 6 (2) 7/2 (3) 4 (4) 9/2

If the curves y^2=6x , 9x^2+by^2=16 intersect each other at right angles then the value of b is: (1) 6 (2) 7/2 (3) 4 (4) 9/2

If the curves y^2=6x , 9x^2+by^2=16 intersect each other at right angles then the value of b is: (1) 6 (2) 7/2 (3) 4 (4) 9/2

If the curves y^(2)=6x,9x^(2)+by^(2)=16 intersect each other at right angles then the value of b is: (1)6(2)(7)/(2)(3)4(4)(9)/(2)

If the curves y^(2) = 16x and 9x^(2)+by^(2) =16 cut each other at right angles, then the value of b is

If the two curves x=y^2 and xy=k cut each other at right angles than a possible value of "K" is

Prove that x^(2)-y^(2)=16 and xy=25 cut each other at right angles.

If x=y^4 and xy=K , cut each other at right angle then Find (4K)^6 =