The present ages for Seeta and Geeta are in the ratio 3:4. The product of their ages (in years) is 48. Find the sum of their ages (in years).

The present ages of Ram and Sita are in ratio of 5:6. The product of their ages (in years) is 120. Find the difference in their ages (in years)

The present ages of Renu and Ravi are in the ratio 5:6. The sum of their present ages is 44 in years.The difference of their ages (in years) is 4 (b) 58 (d) 2

The ratio of the present ages of a father and his son is 3 : 1 . The sum of their ages after five years is 58. Find the ratio of their ages 3 years ago.

The present ages of mary and joseph are in the ratio 5:3 . after 3 years sum of their ages is 38.find their present ages.

The present ages of A and B are in the ratio 3:4 .Twelve years ago ,their ages were in the ratio 2:3 The sum of the present ages of A and B (in years ) is :

The present ages of Manali and Sonali are in the ratio 3:4 . Five years after the ratio of their ages will be 4:5 . Find the present ages.

The present ages of A and B are in the ratio 9 : 4. Seven years hence, the ratio of their ages will be 5 : 3. Find their present ages.