A particle is projected up the inclined such that its component of velocity along the incline is `10 m//s`. Time of flight is `2` sec and maximum height above the incline is `5m`. Then velocity of projection will be

A particle is projected up the incline such that its component of velocity along the incline is 10 ms^(-1) . Time of flight is 4 sec and maximum height above the incline is 5m . Then velocity of projection will be :

If the particle is projected down onto the inclined plane at same speed and angle with the inclined plane the ratio of the time of flight and time of flight for upward projection is :

A projectile is projected on the inclined plane as shown V_(1)&V_(2) are components of it's initial velocity along the incline and perpendicular to incline and V_(3) & V_(4) are components of it's final velocity along the incline and perpendicular to incline. {Here we are comparing the magnitudes only}

A ball thrown down the incline strikes at a point on the incline 25m below the horizontal as shown in the figure. If the ball rises to a maximum height of 20m above the point of projection, the angle of projection alpha (with horizontal x axis) is

An particle is projected with velocity u on an inclined plane at an angle theta with the plane. If the particle lands on the plane at right its time of flight is (u cosec theta)/(2 g) . Find the angle of inclination of the plane with horizontal.