If ABCD is a square, then
`bar(AB) + 2 bar(BC) + 3 bar(CD) + 4 bar(DA)` =

If ABCD is a square then, 2bar(AB)+4bar(BC)+5bar(CD)+7bar(DA)=

If ABCDE is a pentagon, then bar(AB) + bar(AE) + bar(BC) + bar(DC) + bar(ED) =

ABCDE is a regular hexagon. i) If bar(AB) + bar(AE)+ bar(BC) + bar(DC) + bar(ED) + bar(AC)=lambdabar(AC) then lambda=

In the figure 11.34, ABCD is a quadrilateral in which bar(AB) = bar(AD) and bar(BC) =bar(DC). Diagonals bar(AC) and BD intersect each other at O.Show that-

In /_\ABC , D, E, F are the mid-points of bar(AB) , bar(BC) , bar(CA) and if bar(AB) = 11 cm, bar(BC) = 9 cm, bar(CA) = 8cm. Find the lengths of bar(DE) , bar(EF) and bar(DF) .

ABCDE is a pentagon then bar(AB)+bar(AE)+bar(BC)+bar(DC)+bar(ED)+bar(AC)=

In the figure above, ABCD is a square of side 18 cm and bar(PN) bot bar(BC) and bar(PM) bot bar(AB) . Find the length of MN.

If A,B,C,D are four point and |bar(AB) xx bar(CD) +bar(BC)xx bar(AD) +bar(CA) xx bar(BD)| = k ("Area of "DeltaABC) , then k =