The value of `[cos (270^(@) +theta)cos (90^(@) -theta)-sin (270^(@) -theta)cos theta)` is-

Select and write the correct answer from the given alternatives in each of the following:The value of cos(270^@+theta).cos(90^@-theta)-sin(270^@-theta).costheta is=

The value of cos(270^@+theta)cos(90^@+theta)-sin(270^@-theta)costheta is.................. A) 0 B) -1 C) 1/2 D) 1

sin(270^(@)-theta).sin(90^(@)-theta)-cos(270^(@)-theta).cos(90^(@)+theta)=

sin theta cos(90^(@)-theta)+cos theta sin(90^(@)-theta)

Prove that sin (270^(@)-theta) sin (90^(@)-theta)-cos(270^(@)-theta) cos (90^(@)+theta)+1=0

Prove: (iii) "sec" (270^(@) - theta) "sec" (90^(@)- theta) - tan (270^@ - theta) tan (90^(@) + theta) = -1

((cos (90 ^ (@)) - theta) sin (90 ^ (@) - theta)) / (tan (90 ^ (@) - theta))