the matrix `A=[(i,1-2i),(-1-2i,0)], where I = sqrt-1,` is

Let A denote the matrix ({:(0,i),(i,0):}) , where i^(2) = -1 , and let I denote the identity matrix ({:(1,0),(0,1):}) . Then I + A + A^(2) + "….." + A^(2010) is -

1,1+i,2i,-2+2i,"…."where i= sqrt(-1)

Verify that the matrix equation A^(2)-4A+3I = 0 is satisfied by the matrix A={:[(2,-1),(-1,2)]," where " I={:[(1,0),(0,1)]and 0={:[(0,0),(0,0)]. Hence obtain A^(-1).

if matrix A=(1)/sqrt2[(1,i),(-i,a)], i=sqrt-1 is unitary matrix, a is equal to

if matrix A=(1)/sqrt2[(1,i),(-i,a)], i=sqrt-1 is unitary matrix, a is equal to

if matrix A=(1)/sqrt2[(1,i),(-i,a)], i=sqrt-1 is unitary matrix, a is equal to

if matrix A=(1)/sqrt2[(1,i),(-i,a)], i=sqrt-1 is unitary matrix, a is equal to

If A=[(1+2i,i),(-I,1-2i)] , where i=sqrt(-1) , then A(adjA)= . . .

The matrix overset-A={:[(-i,1+2i),(-1+2i,0)]:} is which of the following?

Verify that the matrix equation A^2 - 4a +3I =0 is satisfied by the matrix A = [[2,-1],[-1,2]] , where I = [[1,0],[0,1]] and 0= [[0,0],[0,0]] ,