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" clifferential eá for "Ax^(2)+By^(2)=1"...

" clifferential eá for "Ax^(2)+By^(2)=1" is."

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Show that it the curves ax^(2) +by^(2)=1 " and " Ax^(2) +By^(2) =1 are orthogonal then ab(A-B)=AB(a-b).

Factorise: x^(2) + (a^(2)+1)/ax +1

Factorise : ax^(2)+(a^(2)+1)x+a

The curves ax^(2)+by^(2)=1 and Ax^(2)+B y^(2) =1 intersect orthogonally, then

The curves ax^2+by^2=1 and Ax^2+By^2=1 intersect orthogonally, then

Differentiate tan^-1((1+ax)/(1-ax)) with respect to sqrt(1+a^2x^2)

Differentiate tan^(-1)((1+ax)/(1-ax)) with respect to sqrt(1+a^(2)x^(2))

Differentiate tan^(-1)((1+ax)/(1-ax)) with respect to sqrt(1+a^(2)x^(2))