" if ferential eq "^(n)f_(0)gamma=Ae^(3x)+Be^(-3x)" is."

The differential equation for y=Ae^(3x)+Be^(-3x) is

y = ae^(3x) + be^(-2x)

y = ae^(3x) + be^(-2x)

y = ae^(3x) + be^(-2x)

The order of the differential equation whose solution is ae^(x) + be^(2x) + ce^(3x) + d = 0 is

If alpha, beta and gamma are the roots of the cubic equation (x-1)(x^(2) + x + 3)=0 , then the value of alpha^(3) + beta^(3) + gamma^(3) is:

If f(x)=be^(ax)+ae^(bx) , then f" (0) =

If alpha, beta, gamma are roots of x^(3) + 2x^(2) - 3x - 1 =0, then a^(-2)- beta^(-2) + gamma^(-2) =