Find the equation of the circle drawn on the line-segment joining the foci of the two parabolas `x^(2) = 4ay` and `y^(2)= 4a(x-a)` as diameter .

The equation of the circle drawn on the line segment joining the foci of the two parabolas x ^(2) = 4ayand y^(2) =4a(x-a) as a diameter is-

Find the equation of the circle described on the line segment as diameter joining the foci of the parabolas x^2 =4ay and y^2 = 4a(x-a) as diameter.

Find the equation of the circle described on the line segment joining the foci of the parabolas x^2 - 4ay and y^2 = 4a(x-a) as diameter.

Find the equation of the circle drawn on the line joining (-1,2) and (3, -4) as diameter.

Find the equation of the circle, passing through the origin and the foci of the parabolas y^(2) = 8x and x^(2) = 24 y .

Equation of the line joining the foci of the parabola y^(2)=4x and x^(2) = -4y is

Equation of tangent to parabola x^(2)=4ay

Let P_(1) : y^(2) = 4ax and P_(2) : y^(2) =-4ax be two parabolas and L : y = x be a straight line. if a = 4, then the equation of the ellipse having the line segment joining the foci of the parabolas P_(1) and P_(2) as the major axis and eccentricity equal to (1)/(2) is

Find the general equation of the circle whose diameter is the line segment joining the points (-4,-2) and (1,1)