Home
Class 12
CHEMISTRY
[" The conductivity of "0.001M" acetic a...

[" The conductivity of "0.001M" acetic acid is "],[4times10^(-5)S/cm." Calculate the dissociation constant "],[" of acetic acid,if molar conductivity at infinite "]

Promotional Banner

Similar Questions

Explore conceptually related problems

The conductivity of 0.001M acetic acid is 4 times 10^-8 S//cm . Calculate the dissociation constant of acetic acid, if molar conductivity at infinite dilution for acetic acid is 390 S cm^2//mol .

The conductivity of 0.001 M actic acid is 4 xx 10^(-5) S //cm . Calculate the dissociation constant acetic acid, if molar conductivity at infinite dilution for acetic acid is 390 S cm^(2) // mol.

The conductivity of 0.001 M acetic is 4 xx 10^(-5)S//cm. Calculate the dissociation constant of acetic acid, if molar conductivity at infinite dilution for acetic is 390 S cm^(2)//mol.

The conductivity of 0.001 M acetic is 4 xx 10^(-5)S//cm. Calculate the dissociation constant of acetic acid, if molar conductivity at infinite dilution for acetic is 390 S cm^(2)//mol.

The conductivity of 0.001M acetic acid is 4X10^(-2)S//m . Calculate the dissociation constant of acetic acid if lambda_m^@ for acetic acid is 390Scm^2mol^(-1) .

The conductivity of 0.001028M acetic acid is 4.95xx10^(-5)Scm^(-1) . Calculate its dissociation constant if Lambda_(m)^(0) for acetic acid is 390.5Scm^(2)mol^(-1) .

The conductivity of "0.001028 mol.L"^(-1) acetic acid is 4.95xx10^(-5)"S.cm"^(-1) . Calculate its dissociation constant if Lambda_(m)^(@) for acetic acid is "390.5 S.cm"^(2)."mol"^(-1) .

The conductivity of 0.001028 M acetic acid is 4.95xx10^(-5) S cm^(-1) . Calculate dissociation constant if wedge_(m)^(@) for acetic acid is 390.5 S cm^(2) mol ^(-1) .