A particle is moving at uniform speed `2 ms^(-1)` along a circle of radius `0.5m`.The centripetal acceleration of particle is

A particle is moving with uniform speed 0.5 m//s along a circle of radius 1m then the angular velocity of particle is (in rad s^(-1) )

A particle with the constant speed in a circle of radius r and time period T.The centripetal acceleration of a particle is

A particle with the constant speed in a circle of radius r and time period T.The centripetal acceleration of a particle is

A particle is moving on a circular path of radius 0.3 m and rotaing at 1200 rpm. The centripetal acceleration of the particle

A particle of mass m describes a circle of radius r with a uniform speed v. The centripetal acceleration of the pariticle is 4 / r^(2) .What is the magnitude of the linear momentum of the particle ?

A particle of mass m describes a circle of radius r . The centripetal acceleration of the particle is (4)/(r^(2)) . What will be the momentum of the particle ?

A particle of mass m describes a circle of radius r . The centripetal acceleration of the particle is (4)/(r^(2)) . What will be the momentum of the particle ?

The figure shows the total acceleration a = 32 m s^(-2) of a moving particle moving clockwise in a circle of radius R = 1 m . What are the centripetal acceleration a and speed of the particle at the given instant ?

The figure shows the total acceleration a = 32 m s^(-2) of a moving particle moving clockwise in a circle of radius R = 1 m . What are the centripetal acceleration a and speed of the particle at the given instant ?