If the function `f(x)={((sqrt(2+cosx)-1)/(pi-x)^2 ,; x != pi), (k, ; x = pi):}` is continuous at `x = 1,` then k equals:

If f(x)={((sin(cosx)-cosx)/((pi-2x)^2) ,, x!=pi/2),(k ,, x=pi/2):} is continuous at x=pi/2, then k is equal to

If f(x) ={((3sinx-sqrt(3)cosx)/(6x-pi),",",x != (pi)/6),(a, ",",x = pi/6):} is continuous at x = (pi)/6 , then a =

If f(x) ={((3sinx-sqrt(3)cosx)/(6x-pi),",",x != (pi)/6),(a, ",",x = pi/6):} is continuous at x = (pi)/6 , then a =

For what value of k, function f(x)={((k cosx)/(pi-2x)",","if "x ne (pi)/(2)),(3",", "if " x =(pi)/(2)):} is continuous at x=(pi)/(2) then k?

Find the value of k so that the function f defined by f(x)={((kcos x)/(pi-2x)),when x!=pi/2),(0,atx=pi/2):} is continuous at x = (pi)/2 .

f(x) = {((sin 2x)^(tan^(2)2x), x ne pi/4),(k, x = pi/4):} . If f(x) is continuous at x = pi/4 , then k =

If the function f(x)=(sqrt(5+cos x)-2)/((pi-x)^(2)) is continuous at x=pi, find f(pi)