In Arrehenius equation if a graph is plotted between logK and 1/T, the slope of the curve will be:

If a graph is plotted between Iog k and 1/T the slope of the straight line so obtained is given by

A graph plotted between log k vs (1)/(T) is represented by

A graph plotted between log N vs, time gives a slope and intercept equal to:

If a graph is plotted between log (a-x) and t , the slope of the straight line is equal to -0.03 . The specific reaction rate will be

If a graph is plotted between log (a-x) and t , the slope of the straight line is equal to -0.03 . The specific reaction rate will be

In a plot of log.k vs 1/T, the slope'is :

In a plot of log k vs 1/T, the slope is

If a graph is plotted between Ln K and 1//T for the first order reaction, the slope of the strainght line so obtained is given by-