A rod of length L is of non uniform cross-section. Its mass per unit length varies linearly with distance from left end. Then its centre of mass from left end is at a distance. (Take linear density at left end=0).

A rod of length 3 m has its mass per unit length directly proportional to distance x from one of its ends then its centre of gravity from that end will be at

A rod of length 3m and its mass par unit length is directly proportional to the distance x from its one end . The centre of gravity of the rod from that end will be at :-

The linear density of a rod of length L varies as rho=A+Bx where x is the distance from the left end. The distance of centre of mass from O is

There is a rod of length l , its density varies with length as distance of lambda=ax , where x is distance from left end. Find center of mass from left end.

A rod is of length 3 m and its mass acting per unit length is directly proportional to distance x from its one end. The centre of gravity of the rod from that end will be at

The density of a rod of length L varies as rho=A+Bx where x is the distance from the left end. Locate the centre of mass.

The density of a rod of length L varies as rho=A+Bx where x is the distance from the left end. Locate the centre of mass.

The density of a linear rod of length L varies as rho = A+Bx, where x is the distance from the left end. Locate the centre of mass.

A thin bar of length L has a mass per unit length lambda , that increases linerarly with distance from one end. If its total mass is M and its mass per unit length at the lighter end is lambda_(0) , then the distance of the centre of mass from the lighter end is

A thin bar of length L has a mass per unit length lambda , that increases linerarly with distance from one end. If its total mass is M and its mass per unit length at the lighter end is lambda_(0) , then the distance of the centre of mass from the lighter end is