The linear mass density i.e. mass per unit length of a rod of length `L` is given by `rho = rho_(0)(1 + (x)/(L))`, where `rho_(0)` is constant , `x` distance from the left end. Find the total mass of rod and locate `c.m.` from the left end.

The linear mass density (i.e. Mass per unit length) of a rod of length L is given by rho=rho_(0)(x)/(L) , where rho_(0) is constant and x is the distance from one end A . Find the M.I. about an axis passing through A and perpendicular to length of rod. Express your answer in terms of mass of rod M and length L .

The mass per unit length of a non-uniform rod of length L is given by mu = lambdax^2 , where lambda is constant and x is distance from one end of the rod. The distance of the center of mass of rod from this end is

The mass per unit length of a non-uniform rod of length L is given by mu= lamdaxx2 ​, where lamda is a constant and x is distance from one end of the rod. The distance of the center of mass of rod from this end is :-

The mass per unit length of a non - uniform rod of length L is given mu = lambda x^(2) , where lambda is a constant and x is distance from one end of the rod. The distance of the center of mas of rod from this end is

The mass per unit length of a non- uniform rod OP of length L varies as m=k(x)/(L) where k is a constant and x is the distance of any point on the rod from end 0 .The distance of the centre of mass of the rod from end 0 is

If the linear density (mass per unit length) of a rod of length 3 m is proportional to x , where x , where x is the distance from one end of the rod, the distance of the centre of gravity of the rod from this end is.

The density of a non-uniform rod of length 1m is given by rho (x) = a (1 + bx^(2)) where a and b are constants and 0 le x le 1 . The centre of mass of the rod will be at

The density of a non-uniform rod of length 1m is given by rho (x) = a (1 + bx^(2)) where a and b are constants and 0 le x le 1 . The centre of mass of the rod will be at

The density of a non-uniform rod of length 1m is given by rho (x) = a (1 + bx^(2)) where a and b are constants and 0 le x le 1 . The centre of mass of the rod will be at

The density of a linear rod of length L varies as rho = A+Bx, where x is the distance from the left end. Locate the centre of mass.