The gravitational force between a H-atom and another particle of mass m will be given by Newton's law: `F=G (M.m)/(r^(2)`, where r is in km and

The gravitational force between a H-atom and another particle of mass m will be given by Newton's law: F=G(M.m)/r^2 , where r is in the km.

The gravitational force F between two masses m_(1) and m_(2) separeted by a distance r is given by F = (Gm_(1)m_(2))/(r^(2)) Where G is the universal gravitational constant. What are the dimensions of G ?

The gravitational force between two point masses m_(1) and m_(2) at separation r is given by F = k(m_(1) m_(2))/(r^(2)) The constant k doesn't

The gravitional force between two point masses m_(1) and m_(2) at separation r is given by F=k (m_(1)m_(2))/r^(2) The constant k

Assertion : Mass of the rod AB is m_(1) and of particle P is m_(2) . Distance between centre of rod and particle is r. Then the gravitational force between the rod and the particle is F=(Gm_(1)m_(2))/(r^(2)) Reason : The relation F=(Gm_(1)m_(2))/(r^(2)) can be applied directly only to find force between two particles.

Assertion : Mass of the rod AB is m_(1) and of particle P is m_(2) . Distance between centre of rod and particle is r. Then the gravitational force between the rod and the particle is F=(Gm_(1)m_(2))/(r^(2)) Reason : The relation F=(Gm_(1)m_(2))/(r^(2)) can be applied directly only to find force between two particles.

According t Newton's law of gravitation,force between two point masses , m_1 and m_2 ,separated by a distance ,d is given by F=G (m_1 m_2)/(d^2) . Here,sonstant G depend on:

The gravitational force between two particles of masses m_1 and m_2 seperated by certain distance in air medium is F. If they are taken to vaccum and seperated by the same distance, then the gravitational force between them will be