A particle sides down from rest on an inclined plane of angle `theta` with horizontal. The distances are as shown. The particle slides down to the position `A`, where it velocity is `v`.
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An particle is projected with velocity u on an inclined plane at an angle theta with the plane. If the particle lands on the plane at right its time of flight is (u cosec theta)/(2 g) . Find the angle of inclination of the plane with horizontal.

A block is at rest on an inclined plane making an angle alpha with the horizontal . As the angle alpha of the incline is increased the block starts slipping when the angle of inclination becomes theta . The coefficient of static friction between the block and the surface of the inclined plane is or A body starts sliding down at an angle theta to the horizontal. Then the coefficient of friction is equal to

A cubical block rests on an inclined plane with four edges horizontal.If mu = 1/sqrt3 determine the angle when the block just slides down the plane.

A block is released from the top of an inclined plane of inclination theta . Its velocity at the bottom of plane is v . If it slides down a rough inclined plane of the same inclination , its velocity at bottom is v//2 . The coefficient of friction is

A solid cylinder of mass M and radius R rolls from rest down a plane inclined at an angle theta to the horizontal. The velocity of the centre of mass of the cylinder after it has rolled down a distance d is :

A solid cylinder of mass M and radius R rolls from rest down a plane inclined at an angle theta to the horizontal. The velocity of the centre of mass of the cylinder after it has rolled down a distance d is :