Addition of a non-volatile solute causes lowering in vapour pressure of a solvent from`0.8atm` to`0.2atm` . What is the mole fraction of solvent ?

The vapour pressure of pure solvent is 0.8 mm of Hg at a particular temperature. On addition of a non-volatile solute ‘A’ the vapour pressure of solution becomes 0.6 mm of Hg. The mole fraction of component ‘A’ is:

The vapour pressure of pure solvent is 0.8 mm of Hg at a particular temperature. On addition of a non-volatile solute ‘A’ the vapour pressure of solution becomes 0.6 mm of Hg. The mole fraction of component ‘A’ is:

Vapour pressure of pure solvent is 0.8 mm of Hg at a particular temperature. On addition of non volatile solute ‘A’ the vapour pressure of solution become 0.6 mm of Hg. The mole fraction of component ‘A’ is –

Statement Addition of a non-volatile solute causes a depression in vapour pressure. Explanation vapour pressure of a solution is directly proportional to mole fraction of solvent.

The vapour pressure of a solvent A is 0.80 atm. When a non-volatile substance B is added to this solvent Its vapour pressure drops to 0.6 atm what is the mole fraction of B in solution ?

The vapour pressure of pure liquid solvent 0.50 atm. When a non-volatile solute B is added to the solvent, its vapour pressure drops to 0.30 atm. Thus, mole fraction of the component B is

The vapour pressure of a pure liquid is 0.80 atm. When a non-volatile solute is added to this liquid, its vapour pressure drops to 0.60 atm. The mole fraction of the solute in the solution is

The vapour pressure of a solvent decreases by 10 mm of Hg when a non-volatile solute is added to it. The mole fraction of the solute in solution is equal to 0.2. What should be the mole fraction of solvent if the decrease in vapour pressure is to be 20 mm Hg?

The vapour pressure of pure liquid solvent A is 0.80 atm . When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm , the mole fraction of component B in the solution is