A string of length l is fixed at both ends and is vibrating in second harmonic. The amplitude at anti-node is 2 mm. The amplitude of a particle at distance `l//8` from the fixed end is

A string of length l is fixed at both ends and is vibrating in second harmonic. The amplitude at anti-node is 5 mm. The amplitude of a particle at distance l//8 from the fixed end is

A string of length L is fixed at both ends . It is vibrating in its 3rd overtone with maximum amplitude a. The amplitude at a distance L//3 from one end is

A string of length 'L' is fixed at both ends . It is vibrating in its 3rd overtone with maximum amplitude 'a'. The amplitude at a distance L//3 from one end is

A string of length 'l' is fixed at both ends. It is vibrating in its 3^(rd) overtone with maximum ampltiude 'a' . The amplitude at a distance (l)/(3) from one end is = sqrt(p)(a)/(2) . Find p .

A string of length L fixed at both ends vibrates in its first overtone. Then the wavelength will be

Vibrations of string fixed at one end

A string of length l along x-axis is fixed at both ends and is vibrating in second harmonic. If at t=0 , y=2.5mm for incident wave, the equation of standing wave is ( T is tension and mu is linear density)

A string of length L between the two bridges of sonometer wire vibrates in the second harmonic. Its amplitude of vibration is maximum at