The position of a particle moving along x-axis given by `x=(-2t^(3)-3t^(2)+5)m`. The acceleration of particle at the instant its velocity becomes zero is

Position of particle moving along x-axis is given by x=2t^(3)-4t+3 Initial position of the particle is

Position of particle moving along x-axis is given as x=2+5t+7t^(2) then calculate :

Position of particle moving along x-axis is given as x=2+5t+7t^(2) then calculate :

Position of particle moving along x-axis is given as x=2+5t+7t^(2) then calculate :

The displacement of a particle moving along the x-axis is given by equation x=2t^(3)-2"t"^(2)+60t+6 .The possible acceleration of the particle when its velocity is zero is

A particle is moving along a line according to the law s=t^3-3t^2+5 . The acceleration of the particle at the instant where the velocity is zero is

The displacement of a particle moving along the x-axis is given by equation x=2t^(3)-21"t"^(2)+60t+6 .The possible acceleration of the particle when its velocity is zero is

The position of a particle moving along a straight line is given by x =2 - 5t + t ^(3). Find the acceleration of the particle at t =2 s. (x is metere).

If position of a particle at instant t is given by x=3t^(2) , find the velocity and acceleration of the particle.