The equation of the normal to the curve `y=x(2-x)` at the point `(2,\ 0)` is `x-2y=2` (b) `x-2y+2=0` (c) `2x+y=4` (d) `2x+y-4=0`

The equation of the normal to the curve y=x(2-x) at the point (2,\ 0) is (a) x-2y=2 (b) x-2y+2=0 (c) 2x+y=4 (d) 2x+y-4=0

Find the equation of the tangent line to the curve y=(3x^2-1)/x at the point (1,2) is (a) 4x-y-1=0 (b) 4x+y+2=0 (c)x-y-1=0 (d) 4x-y-2=0

Find the equation of the normal to the curve x^2/a^2-y^2/b^2=1 at (x_0,y_0)

The equation of normal to the curve y^2 (2a-x) = x^3 at the point (a, -a) is... A) 2x-3y=5a B) x+2y+3a= 0 C) x-2y+3a= 0 D) x-2y =3a

Find the equation of the normal to the curve x^2+2y^2-4x-6y+8=0 at the point whose abscissa is 2.

Find the equation of the normal to the curve x^2+2y^2-4x-6y+8=0 at the point whose abscissa is 2.

Find the equation of the normal to the curve x^2+2y^2-4x-6y+8=0 at the point whose abscissa is 2.

Find the equation of the normal to the curve x^(2)+2y^(2)-4x-6y+8=0 at the point whose abscissa is 2 .

Find the equations of tangents and normals to the curve at the point on it: y= x^2 + 2e^x +2 at (0,4)