The electric power transferred by a cell to an external resistance is maximum when the external resistance is equal to (r internal resistance)

Show that the power supplied by a battery to an external reistance is maximum when it is equal to the internal resistance of the batter. Further show that this maximum power is (e^(2))/(4r) where is the emf of the battery and r is internal reisistance.

In the series parallel grouping (multiple arc) of similar cells, the current through the external resistance is maximum, when the value of the external resistance is equal to

Show that to get maximum power in an electrical circuit the external resistance should be equal to the internal resistance.

A battery is of emt E and internal resistance r . The value of external resistance R so that the power across eternal resistance is maximum :

A battery is of emt E and internal resistance R . The value of external resistance r so that the power across eternal resistance is maximum :

An total resistance R is connected to a cell of internal resistance r the maximum current flows in the external resistance, when

If the external resistance is equal to the internal resistance of a cell of emf E. The p.d. across its terminal is

The internal resistance of a cell of emf E is r, and external resistance is R. What is the potential about the external Resistance

An accumulator of emf epsilon and internal resistance r is first connected to an external resistance R_(1) and then to an external resistance R_(2) for the same time. For what value of r the beats dissipated in R_(1) and R_(2) will be same?