" If "f:[-6,6]rarr R" is defined by "f(x)=x^(2)-3" for "x in R" then "(" fofof ")(-1)+(" fofof ")(0)+(" fofof ")(1)=

If f:[-6, 6]rarr RR defined by f(x)=x^(2)-3" for " x in R then (fofof)(-1)+(fofof)(0)+(fofof)(1)=

If f: [-6, 6] -> RR is defined by f(x)=x^2-3 for x in RR then (fofof)(-1)+(fofof)(0)+(fofof)(1)=

Let f:R rarr R be defined by f(x)=x^(2)-3x+4 for the x in R then f^(-1)(2) is

If f:R rarr R is defined by f(x)=x/(x^2+1) find f(f(2))

If f: R rarr R is defined by f(x)=(x)/(x^(2)+1) find f(f(2))

If f: R rarr R be defined by , f(x) = x^2-3x+4 , for all x in R then f^-1(2) is

If f:R rarr R is defined by f(x)=3x+2 define f[f(x)]

Let f : [-6,6] -> R be defined by f(x) = x^2-3. Consider the following 1. (fofof)(-1) = (fofof)(1) 2. (fofof)(-1) - 4(fofof)(1) = (fof)(0) : Which of the above is/are correct?

If f:R rarr(0, 1] is defined by f(x)=(1)/(x^(2)+1) , then f is