In a chemical equilibrium `A + B hArr` C + D, when one mole each of the two reactants are mixed, `0.6` mole each of the products are formed. The equilibrium constant calculated is

1.1 moles of A are mixed with 2.2 moles of B and the mixture is kept in a one litre flask till the equilibrium A+ 2B hArr 2C + D is reached. At equilibrium, 0.2 moles of C are formed. The equilibrium constant of the reaction is

Starting from one mole each of anol and acetic acid, at equilibrium 2//3 mole of ester is formed . Calculate the equilibrium constant.

1.0 mole of ethyl alcohol and 1.0 mole of acetic acid are mixed. At equilibrium, 0.666 mole of ester is formed. The value of equilibrium constant is

1.0 mole of ethyl alcohol and 1.0 mole of acctic acid are mixed. At equilibrium, 0.666 mole of ester is formed. The value of equilibrium constant is

1.1 mole of A are mixed with 2.2 mole of B and the mixture is then kept in a 1 L vessel till the equilibrium : A+2B hArr 2C+D is reached. At equilibrium 0.2 moles of C are formed. The equilibrium constant for the reaction is :

5 mole of X are mixed with 3 moles of Y. At equilibrium for the reaction, X + Y rarr Z 2 moles of Z are formed. The equilibrium constant for the reaction will be

5 mole of X are mixed with 3 moles of Y. At equilibrium for the reaction, X + Y rarr Z 2 moles of Z are formed. The equilibrium constant for the reaction will be