If `f:[-6, 6]rarr RR` defined by `f(x)=x^(2)-3" for " x in R ` then `(fofof)(-1)+(fofof)(0)+(fofof)(1)=`

If f:[-6,6]rarr R is defined by f(x)=x^(2)-3 for x in R then (fofof)(-1)+(fofof)(0)+(fofof )(1)=

If f: [-6, 6] -> RR is defined by f(x)=x^2-3 for x in RR then (fofof)(-1)+(fofof)(0)+(fofof)(1)=

Let f : [-6,6] -> R be defined by f(x) = x^2-3. Consider the following 1. (fofof)(-1) = (fofof)(1) 2. (fofof)(-1) - 4(fofof)(1) = (fof)(0) : Which of the above is/are correct?

If f:R rarr R defined by f(x)=x^(2)-6x-14 then f^(-1)(2)=

If f(x)=x^(2)-1 . Find fofof

If f(x)=-|x| , then (fofof)=

If f:R rarr(0, 1] is defined by f(x)=(1)/(x^(2)+1) , then f is