" If "3tan^(2)theta-4sqrt(3)tan theta+3=0," find the acute angle "theta

If 3 tan^(2)theta - 4sqrt(3)tan theta + 3 = 0, find the acute angle theta .

If 3 tan^(2)theta - 4sqrt(3)tan theta + 3 = 0, find the acute angle theta .

Solve : 3 tan^2 theta - 4sqrt3 tan theta + 3= 0 , find the acute angle

If tan^(2) theta-4sqrt3 * tan theta+3=0,"then" : tan theta=

If 3 tan2theta=sqrt3 find theta .

If tan^(2)theta-(1+sqrt(3))tan theta+sqrt(3)=0, then the general value of theta is

If tan^(2)theta-(1+sqrt(3))tan theta+sqrt(3)=0, then the general value of theta is

tan^(4)theta-(sqrt(3)+1)tan^(2)theta+sqrt(3)=0

Evaluate sin^2 theta - cos^2 theta , if sqrt3 tan theta = 3 sin theta , theta = 0 and theta is an acute angle.