If the line `ax + by +11=0` meets the circle `x^2+y^2 =61` at A, B and `P(-5, 6)` is on the circle such that `PA= PB = 10` then `|a+b|=`______

A line 'I' meets the circle x^2 + y^2 =61 in A, B and P(-5, 6) is such that PA = PB = 10. Then the equation of 'l' is

A line 'I' meets the circle x^2 + y^2 =61 in A, B and P(-5, 6) is such that PA = PB = 10. Then the equation of 'l' is

A line l meets the circle x^(2) + y^(2) = 61 in A , B and P(-5,6) is such that PA = PB = 10 . Then the quation of l is

A line l meet the circle x^(2)+y^(2)=61 in A and B and P(-5,6) is such that P A=P B=10 . Then the equation of l is

The line 2x -y +6= 0 meets the circle x^2+y^2 -2y-9 =0 at A and B. Find the equation of the circle on AB as diameter.

If x-y+1=0 meets the circle. x^(2)+y^(2)+y-1=0 at A and B , then the equation of the circle with A B as diameter is

The line 2x-y+6=0 meets the circle x^(2)+y^(2)-2y-9=0 at A and B. Find the equation of the circle on AB as diameter.

The line 3x -y -17=0 meets the circle x ^(2) +y ^(2) -8x+ 10 y + 5=0 at the point A and B. P is any point on the circle other than A or B, then the triangle APR is