`6a^(2) - 13a + 6 =?`

In the following question two equations are given in variables x and y. you have to solve these equations and determine the relation between x and y. I. 6x^(2) + 13x + 6 = 0 15y^(2) + 13y + 2 = 0

Factorise : 6x^(2) + 13x + 6

Solve the equation: 6x^2 - 13 x + 6=0 .

Divide : 6x^(3) - 13x^(2) - 13x + 30 by 2x^(2) - x - 6

If a^(2) +b^(2) = 13 and ab= 6 find: a^(2) - b^(2)

The figure formed by the pairs of lines 6x^(2) + 13xy + 6y^(2) = 0 and 6x^(2) + 13xy +6y^(2)+ 10x + 10y + 4 = 0 is a

Find a if one zero of (a^(2) +9) x^(2) + 13x + 6a is a reciprocal of the other.

Let's resolve into factor:- 6x^2 - 13x + 6

The asymptotes of the hyperbola 6x^(2) +13xy +6y^(2) -7x -8y-26 =0 are