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Complete the last column of the table...

Complete the last column of the table

Text Solution

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`(i)`
`x + 3= 0 , x = 3`
`L.H.S =x+ 3`, R.H.S = 0
By putting,
`x= 3`
`L.H.S = 3 + 3=6neR.H.S`
Therefore, “No”, the equation is not satisfied.
(ii)`x+ 3 = 0,`
`x= 0`
L.H.S =x+ 3, R.H.S = 0
By putting,
x= 0;
L.H.S = 0+3 = 3 ≠ R.H.S
Therefore, “No”, the equation is not satisfied.
(iii)`x+ 3 = 0,`
`x= -3`
`L.H.S =x+ 3, R.H.S = 0`
By putting,
`x= -3`
`L.H.S = -3 + 3 = 0 = R.H.S`
Therefore, “Yes”, the equation is satisfied.
(iv)
`x – 7 = 1`
,`x= 7`
`L.H.S =x – 7,R.H.S = 1`
By putting,
`x= 7;`
L.H.S = 7 – 7 = 0 ≠ R.H.S
Therefore, “No”, the equation is not satisfied.
(v)
`x – 7 = 1`
,`x= 8`
`L.H.S =x- 7,R.H.S = 1`
By putting,`x= 8;`
`L.H.S = 8 – 7 = 1 = R.H.S`
Therefore, “Yes”, the equation is satisfied
.(vi)` 5x= 25,`
`x= 0`,
L.H.S = 5x , R.H.S = 25
By putting,
x= 0;
L.H.S = 5 0
=0 ≠ R.H.S
Therefore, “No”, the equation is not satisfied.
(vii) 5x= 25,
x= 5,
L.H.S = 5x , R.H.S = 25
By putting,x= 5;
L.H.S =`5xx 5= 25` R.H.S
Therefore, “Yes”, the
equation is satisfied.
(viii)` 5x= 25,`
`x= – 5,`
L.H.S `= 5x`
, R.H.S `=25`
By putting,`x= – 5;`
L.H.S = `5xx(-5)=-25`≠R.H.S
Therefore, “No”, the equation is not satisfied.
(ix )`m/3=2`,m=-6
, R.H.S = 2
By putting,
m= – 6;L.H.S =-6/3
`= −2 ne "R.H.S"`
Therefore, “No”, the equation is not satisfiedL.H.S =m/3
, R.H.S = 2
By putting,
m= 0;
L.H.S =0/3= 0 ≠ R.H.S
Therefore, “No”, the equation is not satisfied.
(xi) m/3=2,m=2
L.H.S =m/3
, R.H.S = 2
By putting,m= 6;
L.H.S =6/3= 2 = R.H.S
Therefore, “Yes”, the
equation is satisfied
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