If `sqrt2=1.414,sqrt3=1.732,sqrt5=2.236, sqrt10=3.162`, then find the values of the following correct to 3 places of decimals .
`sqrt300+sqrt90-sqrt8`

If sqrt2=1.414,sqrt3=1.732,sqrt5=2.236, sqrt10=3.162 , then find the values of the following correct to 3 places of decimals . sqrt40-sqrt20

Given sqrt2 =1.414, find the value of (8-5sqrt2)/(3-2sqrt2) ( to 3 places of decimals ).

It being given that sqrt(2) = 1.414, sqrt(3) = 1.732, sqrt(5) = 2.236 and sqrt(10)= 3.162 , find the value to three places of decimials, of each of the following . (i) (2)/(sqrt(5)) (ii) (2- sqrt(3))/(sqrt(3)) (iii) (sqrt(10) - sqrt(5))/(sqrt(2))

If sqrt(3)=1.732 then find the value 2sqrt(3)-1

If sqrt(2)=1.414, sqrt(3)=1.732 and sqrt(5)=2.236 , find the values of the following. (i) sqrt(98) (ii) sqrt(300) (iii) sqrt(128)+sqrt(48) (iv) 2sqrt(75)-3sqrt(12)

If sqrt(3)=1.732 , then find the value of 4(sqrt(192)-(1)/(2)sqrt(48)-sqrt(75)) correct to 3 places of decimal.