Two particles are executing S.H.M. according to the equations
`x_(1)=6sin(10pit+pi//3)andx_(2)=5cos(8pit+pi//4)`
Then the phase difference between the first and second particle at t = 0.5 s will be

Two particles are executing S.H.M. according to the equations x_(1)=6sin(10pit+pi//3)andx_(2)=6cos(8pit+pi//4) Then the phase difference between the first and second particle at t = 0.5 s will be

Two particles are executing S.H.M. according to the equations x_1 = 6 sin (10 pi t+ pi/3) and x_2 = 6 sin (8 pi t + pi/4) .Then the phase difference between the first and second particle at t = 0.5 s will be

The SHMs are represent by the equation y_(1)=0.1sin(100pit+(pi)/(3))&y_(2)=0.1 cos pit . The phase difference of the velocity of particle is

A particle oscillates with S.H.M. according to the equation x = 10 cos ( 2pit + (pi)/(4)) . Its acceleration at t = 1.5 s is

A particle oscillates with S.H.M. according to the equation x = 10 cos ( 2pit + (pi)/(4)) . Its acceleration at t = 1.5 s is

A particle executes S.H.M., according to the displacement equation x = 6 sin (3pit+pi//6) m. Then the magnitude of its acceleration at t = 2 s is

A particle executes SHM according to the equation, y=4sin( pi t+(pi)/(3)) ,where y is in m and t is in' s '.The phase of particle at time t=0 is

A particle is performing SHM according to the equation x=(3cm)sin((2pit)/(18)+(pi)/(6)) , where t is in seconds. The distance travelled by the particle in 39 s is

A particle executing SHM according to the equation x=5cos(2pit+(pi)/(4)) in SI units. The displacement and acceleration of the particle at t=1.5 s is