The binding energy of deutron `("_1H^(2))` is 1.15 MeV per nucleon and an alpha, particle `("_2He^(4))` has a binding energy of 7.1 MeV per nucleon. Then in the reaction `"_1H^(2)+"_1H^(2)rarr "_(2)He^(4)+Q` The energy Q released in MeV is

The binding energy of deuteron ._1^2 H is 1.112 MeV per nucleon and an alpha- particle ._2^4 He has a binding energy of 7.047 MeV per nucleon. Then in the fusion reaction ._1^2H + ._1^2h rarr ._2^4 He + Q , the energy Q released is.

The binding energy of deuteron ._1^2 H is 1.112 MeV per nucleon and an alpha- particle ._2^4 He has a binding energy of 7.047 MeV per nucleon. Then in the fusion reaction ._1^2H + ._1^2h rarr ._2^4 He + Q , the energy Q released is.

The binding energy of deuteron ._1^2 H is 1.112 MeV per nucleon and an alpha- particle ._2^4 He has a binding energy of 7.047 MeV per nucleon. Then in the fusion reaction ._1^2H + ._1^2h rarr ._2^4 He + Q , the energy Q released is.

The binding energies of deutron (._(1)H^(2)) and alpha - particle (._(2) He ^(4)) are 1. 125 and 7.2 Me V // nucleon respectively . In the process ._(1)H^(2) + ._(1) H^(2) to ._(2) He^(4) Amount of energy transferred is which nucleus is more stable ?

Find the energy Q released in this reaction. 1H^2+1H^2 rarr Q+_2He^4

The binding energies per nucleon for a deuteron and an alpha -particle are x_(1) and x_(2) respectively. What will be the energy Q released in the following reaction? ""_(1)H^(2) + ""_(1)H^(2) to ""_(2)He^(4) + Q