Oxidation state of sulphur in \(H_{2}S_{2}O_{8}\) and \(H_{2}SO_{5}\)

" Oxidation state of sulphur in \(SO_{4}^{-2}\) and \(S_{2}O_{3}^{-2}\)

Oxidation state of sulphur in \(H_{2}S_{2}O_{8}\) IS ''X" and that of chromium in \(CrO_{2}Cl_{2}\) is "Y'' the value of X+Y/4 is

The oxidation state of sulphur in H_(2)S_(2)O_(7) is

Oxidation number of sulphur in H_(2)SO_(5) is

When fluorine react with \(H_{2}S\) a product (X) of sulphur is formed. The difference in the oxidation state of sulphur in \(H_{2}S\) and the product (X) is "

Oxidation states of sulphur in H_2 S_2 O_7 , H_2 SO_3 and H_2 S are respectively

The oxidation number of sulphur in H_(2)S_(2)O_(8) is:

The oxidation state of S in H_(2)S_(2)O_(8) is

Oxidation state of oxygen in H_(2)O_(2) is