If `y=sec^(-1)((1)/(2x^2-1))` find `(dy)/(dx)`.

sec^(-1)((1)/(x-1)) find (dy)/(dx)

y=(1)/(x^(2)) , find (dy)/(dx)

If y = sec^(-1) ((1)/(2x^(2) -1)) " then " (dy)/(dx) = ?

y = sec^(-1)((1+x^(2))/(1-x^(2))), find dy/dx.

If y = sec^-1(1/(2x^2-1)) , then find dy/dx , given 0 < x < 1/sqrt2

If y=sin^(-1)(3x)+sec^(-1)((1)/(3x)), find (dy)/(dx) .

If y=sec^(-1)((x+1)/(x-1))+sin^(-1)((x-1)/(x+1)) , then find (dy)/(dx) .

If y=sec^(-1)((x^(2)+1)/(x^(2)-1)) , then find (dy)/(dx) . Here f^(-1)(x) expression is of the form (x^(2)+a^(2))/(x^(2)-a^(2)) , so we substitute x=tan theta and then use suitable trigonometrical formula to write it in simplest form and then differentiate