Home
Class 10
MATHS
The angle of elevation of a stationer...

The angle of elevation of a stationery cloud from a point 2500 m above a lake is `15o` and the angle of depression of its reflection in the lake is `45o` . What is the height of the cloud above the lake level? (Use `tan15o=0. 268` )

Promotional Banner

Similar Questions

Explore conceptually related problems

The angle of elevation of a stationery cloud from a point 2500 m above a lake is 15o and the angle of depression of its reflection in the lake is 450. What is the height of the cloud above the lake level? (Use tan 15o =0.268)

The angle of elevation of a stationary cloud from a point 25 m above a lake is 30^(@) and the angle of depression of its reflection in the lake is 60^(@) . What is the height of the cloud above that lake-level ?

The angle of elevation of a stationary cloud from a point 2500 mt above a lake is 15^@ and the angle of depression of its reflection in the lake is 45^@ . The height of the cloud is

The angle of elevation of a stationary cloud from a point 2500 feet above a lake is 30^@ and the angle of depression of its reflection in the lake is 45^@ .Find the height of cloud above the lake water surface .

The angle of elevation of a stationary cloud from a point 2500 feet above a lake is 30^@ and the angle of depression of its reflection in the lake is 45^@ .Find the height of cloud above the lake water surface .

The angle of elevation of a stationary cloud from a point 2500 feet above a lake is 30^@ and the angle of depression of its reflection in the lake is 45^@ .Find the height of cloud above the lake water surface .

The angle of elevation of a stationary cloud from a point 200 m above the lake is 30^(@) and the angle of depression of its reflection in the lake is found to be 60^(@) . Find the height of the cloud .