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Given that E^o values of Ag^+//Ag, K^+//...

Given that `E^o` values of `Ag^+//Ag, K^+//K, Mg^(2+)//Mg` and `Cr^(3+) //Cr` are `0.08 V, -2 .93 V, -2 37 V` and ` -0. 74 V` respectively. Therefore the order for the reducing power of the metal is .

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Given that E values of Ag^(+) | Ag, K^(+)|K, Mg^(2+) |Mg and Cr^(3+) | Cr áre 0.80 V,-2.93 V,-2.37 V, and -0.74 V, respectively. Which of the following orders regarding the reducing power of metals is correct?

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Given that the standard electrode (E^(@)) of metals are : K^(+)//K=- 2.93 V, Ag^(+)//Ag = 0.80 V, Mg^(2+)//Mg =- 2.37 V, Cr^(3+)// Cr =- 0.74 V, Hg^(2+)//Hg = 0.79 V . Arrange these metals in an increasing order of their reducing power.

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