The displacement is given by ` x = 2t^(2) + t + 5` , the acceleration at t = 5 sec will be-

The displacement is given by x = 2t^(2) +t +5 , the acceleration at t = 2s is

The displacement of a body is given by x = 2t^(3) - 6t^(2) + 12t + 6 . The acceleration of body is zero at time ti is equal to :

If displacement x at time t is x = sqrt(1+ t^(2)) , then acceleration is

If displacement x at time t is x=sqrt(1+t^(2)) , then acceleration is

If displacement S at time t is S=t^(3)-3t^(2)-15t+12 , then acceleration at time t=1 sec is

Relation between displacement x and time t is x=2-5t+6t^(2) , the initial acceleration will be :-

Relation between displacement x and time t is x=2-5t+6t^(2) , the initial acceleration will be :-

Relation between displacement x and time t is x=2-5t+6t^(2) , the initial acceleration will be :-

If the distance S travelled by a particle in time t is given by s = t^(2) - 2t + 5 then its acceleration is