If the displacement of a particle executing S.H.M. is given by x = 0.24 sin (400 t + 0.5)m, then the maximum velocity of the particle is

The displacement of a particle executing S.H.M. is given by x = 0.34 sin (300 t + 0.68)m. Then its frequency is

The displacement of a particle executing S.H.M. is given by, y = 0.20 sin (100 t) cm. The maximum speed of the particle is

The displacement of a particle executing S.H.M. is given by, y = 0.20 sin (100 t) cm. The maximum speed of the particle is

The displacement of a particle executing S.H.M is given by x= 0.01 sin 100pi (t + 0.05) . The time period is

The displacement of a particle executing S.H.M. is given by y = 0.25 sin 200t cm. The maximum speed of the particle is

If the displacement of a particle executing SHM is given by y=0.30 sin (220t +0.64) in metre , then the frequency and maximum velocity of the particle is

The displacement of a particle executing SHM is given by y=0.5 sin100t cm . The maximum speed of the particle is

The equation of displacement of a particle performing a S.H.M. is x=0.25 "sin" (200 t) metre. What is the maximum velocity of the particle ?

The displacement of a particle executing SHM is given by y=0.25 sin(200t) cm . The maximum speed of the particle is

The displacement equation of a particle executing S.H.M is given by y=0.01 sin pi(t+0.005)m . Calculate the maximum velocity and displacement at the time of start of the motion.