`(1+sintheta-costheta)/(1+sintheta+costheta)=`

((1+sintheta+i costheta)/(1+sintheta-i costheta))^n is equal to

((1+sintheta+i costheta)/(1+sintheta-i costheta))^n is equal to

Prove that: (sintheta-costheta+1)/(sintheta+costheta-1)=1/(sectheta-tantheta)

If (sintheta-costheta+1)/(sintheta+costheta-1)=(x)/(tantheta-sectheta+1) then x =

Prove the following identities : (sintheta-costheta+1)/(sintheta+costheta-1)=1/(sectheta-tantheta)

Prove the following : (sintheta-costheta+1)/(sintheta+costheta-1)=(1)/(sectheta-tantheta) .

(sintheta-costheta+1)/(sintheta+costheta-1) (where theta ne (pi)/(2)) is equal to

Prove that (sintheta-costheta+1)/(sintheta+costheta-1)=1/(sectheta-tantheta) , using the identity sec^2theta=1+tan^2theta

(sintheta+costheta)/(sintheta-costheta)+(sintheta-costheta)/(sintheta+costheta) =_____________.